An Angle Bisector in a Parallelogram Question
Question & Solutions are in image below except the (a) part whose solution is as follows:
EAB = 1/2(BAC)
And
EBA = 1/2(DBA)
So
EAB + EBA
= 1/2(BAC + DBA)
= 1/2(180)
= 90
*Note: EBA = angle (EBA)
So for (a), we write:
AEB
= 180 – (EAB + EBA)
= 180 – 90
= 90
