Question
Find three consecutive integers greater than 2000, such that each integer is a product of exactly three distinct prime numbers.
Solution
A simple way for the above would be to list down the prime factors for the numbers above 2000 & note that the numbers 2013, 2014 & 2015 are a possible answer.
Put the list like this in working:
2001 = 3 x 23 x 29
2002 = 2 x 7 x 11 x 13
Etc.
Until
2013 = 3 x 11 x 61
2014 = 2 x 19 x 53
2015 = 5 x 13 x 31
QED
Powerpoint Slide - Why I wrote the books? An Explanation Update: Update: FYI, as of 23 Dec 2023 total… Read More
New Book Titled Last Book - Possibilities and Dangers of Doctrine Free PDF download link: https://drive.google.com/file/d/1wjDRr6lzDQ-4D60J8sqmDH-S60tCqQIR/view?usp=sharing #LastBook or #PODBook or… Read More
I don't want to write a new book so sorry but please see #MyCV15Oct2023 for latest theological update (hopefully last)… Read More
#BookofDoctrine or #DoctrineBook Latest Update (Free PDF Release): 20 July 2023 Please find the New Book titled "Book of Doctrine… Read More
Latest Update: 6 June 2023 I will just quote some major summary in images (more details in the free pdf… Read More
Latest Update: 28 May 2023 I will just quote some major summary in images (more details in the free pdf… Read More