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  • Integration Question: ∫ [f(x) / (1 + x)^2]dx, where f(x) is a polynomial of degree two in x, such that f(0)=1,f(1)=3,f(-1)=5.?

    Anonymous Christian
    Sep 5, 2014
    MATH
    Comments Off on Integration Question: ∫ [f(x) / (1 + x)^2]dx, where f(x) is a polynomial of degree two in x, such that f(0)=1,f(1)=3,f(-1)=5.?

    Answer

    Since f(x) is a polynomial of degree two in x,
    Let f(x) = ax^2 + bx + c, where a,b,c are constants.

    Let’s find f(x) first.

    f(0) = 1 implies, c = 1.

    f(1) = 3 implies, a + b + c = 3
    or a + b = 2 , or b = 2 – a …(1)

    f(-1) = 5 implies, a – b + c = 5
    or a – b = 4 …(2)

    Substituting (1) into (2), we get,

    a – [ 2 – a ] = 4
    2a = 6 or a = 3.
    Thus, b = 2 – a = 2 – 3 = -1.

    Hence, f(x) = 3x^2 – x + 1

    Note that by long division or by the identity below,

    3x^2 – x + 1 = 3(x + 1)^2 – 7x – 2

    We get,

    [ 3x^2 – x + 1 ] /[1 + x]^2 = 3 – [7x + 2]/ [1 + x]^2

    And that together with below,

    [7x + 2]/ [1 + x]^2 = 7 /(x + 1) – 5 /(x+1)^2

    Gives,

    [ 3x^2 – x + 1 ] /[1 + x]^2 = 3 – 7 /(x + 1) + 5 /(x+1)^2

    Now, we have an “integratable form”.

    ∫ [f(x) / (1 + x)^2] dx

    = ∫ [3x^2 – x + 1] / (1 + x)^2] dx

    = ∫ [ 3 – 7 /(x + 1) + 5 /(x+1)^2 ] dx

    = 3x – 7 log(x + 1) – (5/[x + 1]) + C

    where C is any arbitrary constant.

    Note: Sometimes log(x + 1) can also be written as ln (x + 1)

    Remark. It is generally accepted that log and ln are both in base “e”, the Euler number. If its in a different base, then usually its said or stated. For example logarithm of x in base 2 can be written as log_2(x).
    Just symbols 🙂

anonymous-christian

Jonathan Ramachandran is founder at AnonymousChristian.org which serves as a Christian Blog discussing the Greater Hope of Biblical Christian in Christ Alone. He is also an IMO (International Math Coach) and a featuring Guitarist for many bands.

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