In triangle ABC, angle ABC=15 degrees, angle ACB=30 degrees, AD is the median to side BC, A-D-C. angle BAD=?
Answer We will use the Sine Rule. In triangle ABD, AD / sin(ABD) = BD / sin(BAD) So AD / BD = sin(ABD) / sin(BAD) In triangle ADC, AD / sin(ACD) = CD / sin(CAD) and AD / CD = sin(ACD) / sin(CAD) Since BD = CD, ( because D is median in BC...
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