1 on 1 Math/Olympiad Primary Class in as few as 1 Class in 1 Month is available for booking now, first come first serve basis!   Class Information:   1) Who can join?   Open to any student in the Primary Level (ages 7 to 12) for Math Olympiad Classes. Math Olympiad classes...

Please find the Questions for Day 1 below (Thank you Mr A for sharing it):               Here’s a frail attempt of mine to try solve Problem 1 to celebrate this remarkable Mathematical Competition.                              ...

Please find my attempt at Solutions for the OMK 2018 Olimpiad Matematik Kebangsaan Malaysian Highest-Sulong Category (Form 5, Lower & Upper Sixth Form, ages 17 to 19 inclusive) for the Malaysian National Mathematical Olympiad 2018. Question and Solutions are in Images below. Please try the questions by yourself first before looking at the suggested...

Firstly,  to avoid copyright problems we only are present solutions to a few selected (sample) questions from the Hong Kong Mathematical Olympiad HKMO 2015 . Also, each solution presented here is purely our work and we did not copy from the HKMO official solutions. This same is true for every Math Olympiad Problem found...

Question No. 25 of the ASMO  (Math Olympiad) in Image             A Possible Solution       To Get a sum of zero, we need a minimum of 8 addends from the Counting Numbers 1 to 9 as described as follows:     Up or Down 2, 4, 6,...

Question (in Image below)   (SMOPS 2015 No.30 ) In the following figure, not drawn to scale, B, D, E and C lie on a straight line. Given that angle (BAD) = angle (DAE) = 12 degrees, AC is perpendicular to AD, and BC = AB + AE, find angle (ABC) in degrees.  ...

Question (SMOPS 2015 No.12) Given that 2^29 is a number comprising of 9 different digits, which digit is not in this number?         Solution (Please refer to Image below)              

Question in Image Below         Solution 22) Fact   Perfect Squares can only have last digits 0, 1, 4, 5, 6, 9   Perfect Square CANNOT have these last digits: 2, 3, 7, 8 If (i) and (ii) were true, a number with last digit 2 is a perfect square, impossible!...

SASMO Question in Image below     Solution   21) Notice that   9 = 10 – 1   99 = 100 – 1   999 = 1000 – 1   . . .   999…999 (2017 digits) = 10^2017 – 1   So   A = (10^1 + 10^2 + 10^3 + …...

    KMC 2017 Cadet No. 30 Quadrilateral Area within a Parallelogram   Question and Solution are in Images below: